
{"id":3544,"date":"2005-09-28T00:17:00","date_gmt":"2005-09-27T15:17:00","guid":{"rendered":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/?p=3544"},"modified":"2021-08-12T11:56:33","modified_gmt":"2021-08-12T02:56:33","slug":"la2k5fallpractice0920","status":"publish","type":"post","link":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/2005\/09\/28\/la2k5fallpractice0920\/","title":{"rendered":"LA2k5FallPractice0920"},"content":{"rendered":"<p> <code>=<\/code> 9\/20 \uc5f0\uc2b5 \ub0b4\uc6a9 <code>=<\/code> &#8221;&#8217;\uace0\uccd0\ub193\uc558\uc5b4\uc694. &#8211; \uae40\uc601\uc6b1&#8221;&#8217; <\/p>\n<p> \\[ 16. ~\\text{ Suppose that u,v, and w are vectors such that}<u> =2, = -3,<u> = 5,|u| = 1, \\] \\[ |v|=2, |w|=7 \\] <code>~$$ ~<\/code>\\text{ Evaluate the given expression. }~~ \\text{(a)} <code>~&lt; u+v,v+w&gt; ~~~<\/code> \\text{(b)}~~ &lt; 2v-w ,3u+2w&gt; $$ <\/p>\n<p> Ans of (a) : \\[ <u> = <u> + <u> +  +  = 2 + 5 +4 -3 = 8 . \\] <\/p>\n<p> Ans of (b) : \\[  = 6  +4  -3  -2  = 12 -12 -15-98 = -113 . \\] <\/p>\n<p> \\[ 21. ~\\text{ Show that the following identity holds for vectors in any inner product space.} \\] <\/p>\n<p> \\[ <u> = {\\frac14} |u+v|^2 &#8211; \\frac14 |u-v|^2 \\] <\/p>\n<p> Ans : \\[ Since~~ |u+v|^2 = <u> = <u> + <u> +  +  \\] \\[ Since~~ |u-v|^2 =  = <u> &#8211; <u> &#8211;  +  \\] \\[ Thus~~~ |u+v|^2 &#8211; |u-v|^2 = 4 <u> . \\] <\/p>\n<p> \\[ 24. ~\\text{ Prove : If } <u> \\text{is the Euclidean inner product on}~ R^n ,\\text{ and if}~ A~ \\text{is an} \\] n\u00d7n \\[ \\text{matrix , then} \\] \\[ <u> = <A> \\] <\/p>\n<p> Ans : \\[ \\text{Since} <u>= (Av)^T u = v^T A^T u = v^T (A^T u) = <A> . \\] <\/p>\n<p> \\[ 27. ~\\text{ Use the inner pruduct to compute} \\] \\[ <\/p>\n<p> \\text{for the vectors p=p(x) and q=q(x) in} P_3 \\] <\/p>\n<p> \\[ ~~~~~~~~~~~~~~~<\/p>\n<p>= \\int_{-1}^1~~ p(x)q(x)~ dx \\] <\/p>\n<p> Ans : Check first this is inner product. <\/p>\n<p> \u2460 \\[ <\/p>\n<p>= \\int_{-1}^1~~ p(x)q(x)~ dx ~~~~~~ <q>= \\int_{-1}^1~~q(x)p(x) ~ dx \\] <\/p>\n<p> \u2461 \\[ <\/p>\n<p> = \\int_{-1}^1~~ p(x)[q(x)+r(x)]~ dx = \\int_{-1}^1~~p(x)q(x)~dx ~~+\\int_{-1}^1~~p(x)r(x)~dx ~~then ~ <\/p>\n<p>= <\/p>\n<p> + <\/p>\n<p>~ \\] <\/p>\n<p> \u2462 \\[  = \\int_{-1}^1~~ [kp(x)]q(x)~ dx ~~=k\\int_{-1}^1~~ p(x)q(x)~ dx ~~\\] <\/p>\n<p> \u2463 \\[ <\/p>\n<p> = \\int_{-1}^1~~ p(x)^2~ dx~ \\geq 0 ~~ \\text{Since} ~~ p(x)^2 \\geq 0 ~~~ \\text{and}~~ <\/p>\n<p> =0 ~~\\text{iff}~~ p(x)=0 \\] <\/p>\n<p> And we sloved the problem &#8221;&#8217;31&#8221;&#8217;. <\/p>\n<p> \\[ 19. \\text{ Let V be an inner product space. Show that if}~ u~\\text{ and}~ v \\text{ are orthogonal unit vectors in}~ V, \\text{ then}~ |u-v| = \\] <\/p>\n<p> Ans : \\[ \\text{ Since }~ u \\text{ and}~ v \\text{ are orthogonal, then} \\] \\[ <u> = o ~\\text{and Since}~ u \\text{ and}~ v \\text{ are a unit then}~ |u|=|v|=1 \\] \\[ \\text{Thus}~ |u-v|^2 =  = <u> &#8211; 2<u> +  = 1+1 =2 . \\] <\/p>\n<p> \\[ 24. \\text{ Prove the following generalization of Theorem 6.2.4. If }~v_1, v_2 , \\dots , v_r \\text{ are pairwise orthogonal vectors in an inner product space in V,} \\] \\[ \\text{ then} ~ |v_1 + v_2 + \\dots + v_r |^2 = |v_1|^2 + \\dots +|v_r|^2 \\] <\/p>\n<p> Ans : \\[ \\text{ Since}~ v_i&#8217;s \\text{ are pairwise orthogonal, then}~ =0 \\text{ if } i\\neq j . \\text{thus proved.} \\] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>= 9\/20 \uc5f0\uc2b5 \ub0b4\uc6a9 = &#8221;&#8217;\uace0\uccd0\ub193\uc558\uc5b4\uc694. &#8211; \uae40\uc601\uc6b1&#8221;&#8217; \\[ 16. ~\\text{ Suppose that u,v, and w are vectors such that} =2, = -3, = 5,|u| = 1, \\] \\[ |v|=2, |w|=7 \\] ~$$ ~\\text{ Evaluate the given expression. }~~ \\text{(a)} ~&lt; u+v,v+w&gt; ~~~ \\text{(b)}~~ &lt; 2v-w ,3u+2w&gt; $$ Ans of (a) : \\[ = + &#8230; <a title=\"LA2k5FallPractice0920\" class=\"read-more\" href=\"https:\/\/mathematicians.korea.ac.kr\/ywkim\/2005\/09\/28\/la2k5fallpractice0920\/\" aria-label=\"LA2k5FallPractice0920\uc5d0 \ub300\ud574 \ub354 \uc790\uc138\ud788 \uc54c\uc544\ubcf4\uc138\uc694\">\ub354 \uc77d\uae30<\/a><\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"ngg_post_thumbnail":0,"footnotes":""},"categories":[1],"tags":[],"class_list":["post-3544","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"distributor_meta":false,"distributor_terms":false,"distributor_media":false,"distributor_original_site_name":"\uae40\uc601\uc6b1","distributor_original_site_url":"https:\/\/mathematicians.korea.ac.kr\/ywkim","push-errors":false,"_links":{"self":[{"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/posts\/3544","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/users\/7"}],"replies":[{"embeddable":true,"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/comments?post=3544"}],"version-history":[{"count":1,"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/posts\/3544\/revisions"}],"predecessor-version":[{"id":3545,"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/posts\/3544\/revisions\/3545"}],"wp:attachment":[{"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/media?parent=3544"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/categories?post=3544"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mathematicians.korea.ac.kr\/ywkim\/wp-json\/wp\/v2\/tags?post=3544"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}